In the following quadratic equations, factor out a constant, if possible: $8x^2+4x-10=0$$2x^2-6x+9=0$$4x^2-4x=-20$$8x^2=4x-8$$3x^2+6=-36x$$2x^2-6x+6=0$$-6x+18=12x^2$$5x^2-2x+10=0$$6x^2+6x+6=0$$3x^2-12x=-12$ Answer Key: Factoring out a Constant Practice AK