Functions Practice AK
$f(x)=3x+7$
Find the value of:
- $f(2)= \mathbf{3(2)+7=13}$
- $f(3)= \mathbf{3(3)+7=16}$
- $f(5)= \mathbf{3(5)+7=22}$
- $f(10)= \mathbf{3(10)+7=37}$
$f(2)=7$
- Which of the following could be f(x)?
- $f(x)=x+2 = 2+2=4$ no
- $f(x)=x^2-1= 4-1=3$ no
- $f(x)=3x-1= 6-1=5$ no
- $f(x)=x^2-2= 4-2=2$ no
- ${f(x)=x^3-1= \mathbf{8-1=7}}$ yes
$f(x)=2x-4$
$g(x)=\dfrac{x}{2}+3$
Find the value of:
- $f(4)=2(4)-4=4$
- $g(3)=\dfrac{3}{2}+3=4.5$
- $f(g(2))=f(\dfrac{2}{2}+3)=f(4)=2(4)-4=4$
- $g(f(1))=g(2(1)-4)=g(-2)=\dfrac{-2}{2}+3=-1+3=2$
- $f(g(f(2)))=f(g(2(2)-4)=f(g(0))=f(\dfrac{0}{2}+3)=f(3)=2(3)-4=2$