$(6+\sqrt{19})(2-\sqrt{7})$$(7+3\sqrt{2})(3-2\sqrt{2})$$(3\sqrt{2}+2\sqrt{3})(1-\sqrt{7})$$(2-2x)(4+\sqrt{x})$$(\sqrt{x}-\sqrt{2})(6+\sqrt{2})$$(2-\sqrt{3})(x+\sqrt{3})$$(3+4i)(6-14i)$$(4-4i)(3-4i)$ Answer Key: Multiplying Binomials with Radicals
