Solve for the variable:$4^a=16$$5^y=125$$2^x=64$$10^p=1$$25^b=5$$7^{r-9}=49$$3^{n+5}=81$$2^{2x-3}=32$$(3^x)(3^{x-1})=3^5$$(2^{2y})(2^{y+1})=16$$(2^x)^3=8$$(3^{3x+1})^2=27$ Answer Key: Solve for a Variable in an Exponent
